How to Calculate Isht Nadi?

When the isht 50 ghari 5 pals is deducted from 60 gharis
of day and night we get a remainder
of 9 ghari and 55 pal. 9 gharis are
converted into pal, It means 9 is multiplied by 60 to get the product 540 to which 55 pals are added to make 595. A deduction of 307 from this will leave 278. When 30 anshas are made by picking up one number
from these will have 287. When 25 anshas are deducted from 30 anshas
5 will be left. Now, 60 kulas are made by pecking up one number from 5. The other four will remain
as they are. When 9 Kulas will be taken
out from 60 kulas there
will remain 51 kulas. Of them 50 are taken while one kula is converted
into 60 bakula out of which
59 are deducted and one bakula will remain
there. The result will be 287 Rashi, 9 ansh, 50 kula, 10 bakula 359 pals of Leo of the previous
Rashi were to be deducted
from the number of Rashi which cannot be less than 287. Therefore, the Rashi remained impure
(ashudh).

287 multiplied by 30 gives the product 8610.
When 4 is added to it the total will be 8414. Now, this total will be divided by 359 pals of Leo in ashudh raans
which gives a quotient 33 to be placed
in the first grade. The remaining 357 is multiplied by 60 to make 21420.
The addition of 50 Kula to this product
will make 21470.
This total is divided by 359 pals to bring a quotient 59 which is
placed on the seemed grade. The
remaining 2895 is multiplied by 60 to get the
product 17340 which I bakula
is added to make 17341.
This total is divided by 359 pals to bring
a quotient 48. The result
is 22 ansh, 59 hula and 48
bakula.

Now, due to Bhagat
we deduct it from ashuddh
Rashi, and 20 anshas are developed by picking one of
the five Rashias while there remain
four out of 30 ansh 23 are deducted while there
remain 7. One of them is Converted into 60 Kular while these remain 6. When 59 Kules are deducted
from 60 Kules there remains
just one kule. That too is converted into
60 bakula while there remains zero. When 48 bakulas is deducted from 60 bakula we are left with 12 bakulas. The final result
is: